Defines interface of numconv.c functions (do not modify)
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| char | int2char (int radix, int digit) |
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| int | char2int (int radix, char digit) |
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| void | divRem (int numerator, int divisor, int *quotient, int *remainder) |
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| int | ascii2int (int radix, const char *str) |
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| void | int2ascii (int radix, int value) |
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| double | ascii2double (int radix, const char *str) |
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This file defines the interface to a C file numconv.c that you will complete. You will learn how to use the C language operators for address-of (&), and dereferencing pointers *). This will serve as a model when you implement the same functions in LC3 assembly language.
| double ascii2double |
( |
int |
radix, |
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const char * |
str |
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) |
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Convert the string to a double. This function is for extra credit.
- Parameters
-
| radix | - the base you are working in (2-36) |
| str | - the string may contain the character '.' and the characters that follow it are the fractional portion of the number, |
- Returns
- the value as a double or -1.0 on error.
- Todo:
- implement in
numconv.c based on documentation contained in numconv.h.
| int ascii2int |
( |
int |
radix, |
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const char * |
str |
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) |
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Convert a string to an integer value
- Parameters
-
| radix | - the base you are working in (2-36) |
| str | - the string |
- Returns
- the number represented by the string or -1 on error
- Todo:
- implement in
numconv.c based on documentation contained in numconv.h.
| int char2int |
( |
int |
radix, |
|
|
char |
digit |
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) |
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Return the value corresponding to the character.
- Parameters
-
| radix | - the base you are working in (2-36) |
| digit | - character '0' .. '9' or 'A'..'Z' 'a' .. 'z' |
- Returns
- value in the range of
0 - (base-1) if c is valid in the base. Otherwise return -1;
- Todo:
- implement in
numconv.c based on documentation contained in numconv.h.
| void divRem |
( |
int |
numerator, |
|
|
int |
divisor, |
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int * |
quotient, |
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int * |
remainder |
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) |
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Calculate both the quotient and remainder of a division and return the values via pointers. You may use the C operators for division (/) and modulus (%). However, you might want to write a loop to using repeated subtraction do the calculations to help you understand how you will implement this in LC3 assembly language (which has no operators for division or modulus).
- Parameters
-
| numerator | - non-negative value for numerator |
| divisor | - a positive value to divide by |
| quotient | - a pointer to the location to store the result of division |
| remainder | - a pointer to the location to store the remainder |
- Todo:
- implement in
numconv.c based on documentation contained in numconv.h.
| void int2ascii |
( |
int |
radix, |
|
|
int |
value |
|
) |
| |
Print a number in the specified base. Use the C call putchar() to print a single character obtained using int2char(). This corresponds to the OUT instruction of the LC3 OS. You may not use any other C I/O routine for printing. This function MUST be implemented recursively. Your program can not use arrays or strings in C, even if you know about them.
- Parameters
-
| radix | - the base you are working in (2-36) |
| value | - the number to print |
- Todo:
- implement in
numconv.c based on documentation contained in numconv.h.
| char int2char |
( |
int |
radix, |
|
|
int |
digit |
|
) |
| |
Return the character corresponding to the digit.
- Parameters
-
| radix | - the base you are working in (2-36) |
| digit | - a value in the range of 0 - (base-1) |
- Returns
- - character '0' .. '9' or 'A'..'Z' if the value is legal. Otherwise return '?'
- Author
- your name goes here
- Todo:
- implement in
numconv.c based on documentation contained in numconv.h.
