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CS253 Const

const

• const, when applied to a variable, means that you can’t change it.
• It’s like a final variable in Java.
• It does not mean that the memory is read-only; it just means that you can’t write it.
• A given piece of memory may be read-only to one part of a program, but read-write to another.
• const is also used to indicate an accessor member function.

Example

const int BOARD_SIZE = 8;
char chessboard[BOARD_SIZE][BOARD_SIZE];
for (int i=0; i<BOARD_SIZE; i++)
    for (int j=0; j<BOARD_SIZE; j++)
        chessboard[i][j] = ' ';

if (chessboard[3][2] == ' ')    // Empty position?
    chessboard[3][2] = 'R';     // put a rook there

cout << chessboard[3][2] << '\n';

R

Reference example

void show_name(const string &name) {
    cout << "The name is: “" << name << "”\n";
}

int main(int, char *argv[]) {
    string s = argv[0];
    show_name(s);
}

The name is: “./a.out”

• The string is read-write in main(), but read-only in show_name().
• The string memory itself is read-write. It’s just that show_name() promises not to change it.

constexpr

• constexpr, when applied to a variable, means that you can’t change it, like const.
• It also means that the value was computed at compile-time.
• The compiler is entitled to assume that the value never changes, so it can substitute the value wherever you use the variable.
• Use it for true constants:
  • π, Avogadro’s Number
  • number of days in a week
  • number of squares in a chessboard

Examples

constexpr auto pi = 3.14159;
cout << pi << '\n';

3.14159

constexpr double avo=6.022e23;
avo = 1.234;
cout << avo;

c.cc:2: error: assignment of read-only variable 'avo'

Trying to cheat

Let’s try to fool constexpr:

constexpr int answer = 42;
int *p = &answer;
*p = 8675309;
cout << answer << '\n';

c.cc:2: error: invalid conversion from 'const int*' to 'int*'

constexpr int answer = 42;
int *p = const_cast<int *>(&answer);
*p = 8675309;
cout << *p << ' ' << answer << '\n';

8675309 42