====== Change of Basis ======
Change of basis is a useful transformation in a lot of aspect. This page shows how to use command CoB to apply change of basis on a program.
===== Usage =====
Here is the usage for CoB:
CoB(Program program, String systemName, String varName, String function)
The meaning for each parameters are:
* program: the program you are processing.
* systemName: the name for the system you want to solve.
* varName: the name for the variable you want to apply change of basis on.
* function: change of basis function.
===== Example =====
The following example does a matrix multiplication, C = A*B.
affine matrix_product {P, Q, R|P>0 && Q>0 && R>0}
given float A {i,k| 0<=i= 0} : ((i,j,k->i,j,k-1)@temp_C + ((i,j,k->i,k-1)@A * (i,j,k->k-1,j)@B));
{i,j,k|k== 0} : (i,j,k->)@0;
esac;
C = (i,j,k->i,j,k)@temp_C;
.
Now we are going to apply change of basis on variable "temp_C" using function (i,j,k->i,j,k+1). We can apply the transformation with the following code:
prog = ReadAlphabets("matrix_product.ab");
system = "matrix_product";
CoB(prog, system, "temp_C", "(i,j,k->i,j,k+1)");
The result for this transformation is shown below:
affine matrix_product {P, Q, R|P>0 && Q>0 && R>0}
given float A {i,k| 0<=ii,j,k-1)@case
{i,j,k|k-1>= 0} : ((i,j,k->i,j,k-1)@(i,j,k->i,j,k+1)@temp_C + ((i,j,k->i,k-1)@A * (i,j,k->k-1,j)@B));
{i,j,k|k== 0} : (i,j,k->)@0;
esac;
C = (i,j,k->i,j,k)@(i,j,k->i,j,k+1)@temp_C;
.
We applied the change of basis function (i,j,k->i,j,k+1) on variable "temp_C", which means we shifted the domain of "temp_C" along k direction by one unit. We can see that the domain for "temp_C" is changed from:
float temp_C {i,j,k|0<=i
to
float temp_C {i,j,k|0<=i
And all the access functions for temp_C is composed with function (i,j,k->i,j,k+1). For example, the access function in the computation of C is changed from
C = (i,j,k->i,j,k)@temp_C;
to
C = (i,j,k->i,j,k)@(i,j,k->i,j,k+1)@temp_C;